Question

radius of a circle with O is 41 units.Length of a chord PQ is 80 onits, find the distance of the chord from the centre of the circle

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

The distance of the chord from the centre of the circle is 9 units.

Step-by-step explanation:

We have

radius = 41 unit, chord = 80

If we draw a perpendicular on chord than it divides chord in two equal parts

Let the length of the perpendicular be p

By pythagorean theorem

$h^2 = p^2 + b^2\\r^2 = p^2 + (40)^2$

$(41)^2 = p^2 + (40)^2\\1681 = p^2 + 1600\\p^2 = 1681 - 1600 \\p^2 = 81\\p = \sqrt{81} \\p = 9$

So, the distance of the chord from the centre of the circle is 9 units.