Math, asked by survivors65, 4 months ago

radius of a sphere is increased by P %. Its surface area

increases by​

Answers

Answered by mishrasweekruti05
0

Answer:

Let the initial radius be r . When it is raised by P % , new radius will be r + rP 100 Initially its surface area was 4 πr 2 Now , the new surface area will be 4 π r + rP 100 2 Surface area is increased by 4 π r + rP 100 2 - 4 πr 2 = 4 πr 2 1 + P 100 2 - 4 πr 2 = 4 πr 2 P 2 10000 + 2 P 100 So , percentage increase

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