Radius of an iron sphere is 0.21 cm .if density of iron is 7.80g/cc,calculate its mass
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volume of iron sphere = 4/3πr³
= 4/3× 22/7 × (0.21)³ cm³
=4× 22× 0.1 ×0.0441 cm³
=0.38808 cm ³
density = mass/volume
mass = density × volume
= 7.8 × 0.38808 g
=3.02 g
= 4/3× 22/7 × (0.21)³ cm³
=4× 22× 0.1 ×0.0441 cm³
=0.38808 cm ³
density = mass/volume
mass = density × volume
= 7.8 × 0.38808 g
=3.02 g
Answered by
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Hi there !!
Radius = r = 0.21cm
Density = 7.80 g/ cm³
Volume of a sphere = 4/3πr³
= 4/3 × 22/7 × 0.21 × 0.21 × 0.21
= 0.38808 cm ³
Density = Mass ÷ Volume
Mass = Density × Volume
= 7.80 × 0.38808
= 3.02 grams [ approx.]
Radius = r = 0.21cm
Density = 7.80 g/ cm³
Volume of a sphere = 4/3πr³
= 4/3 × 22/7 × 0.21 × 0.21 × 0.21
= 0.38808 cm ³
Density = Mass ÷ Volume
Mass = Density × Volume
= 7.80 × 0.38808
= 3.02 grams [ approx.]
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