Question

Radius of circle is 10 cm and distance of chord from the centre is 6 cm. Find length of that chord.​

Answer 1

LETS TAKE TRIANGLE AOB

OA=OB

OA=OB

angle ODA=angle ODB

HENCE ∆OAD~OBD

AO^2=AD^2 + OD^2

10^2= AD^2 + 6^2

100=AD^2 +36

AD^2 = 100-36

=64

AD= √64=8

FROM ABOVE, AD=DB

AB=2AD

=2×8

=16

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Answer 2

Here is the final answer.