Question

radius of circle is 10 cm. There are two chord of length 16 cm each. what will be the distance of these chord from the center of the circle?​

Answer 1

Given :- Length of the chord AB = 16cm and radius ( r ) = 10cm .

To find :- OM

Construction :- Draw a perpendicularOM from centre O such that, it bisects the chord AB.

Proof :- In right angled ∆OMB,

OB^2 = OM^2 + BM^2

=> 10^2 = OM^2 + 8^2

=> 100 = OM^2 + 64

=> OM^2 = 36

=> OM = √36

=> OM = 6 cm

Hence, the distance of the chord from the centre of the circle is 6cm.

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