Question

Radius of circle is 10 cm. There are two chords of length 16 cm. What will be the distance of these chords from the centre of the circle​?

Answer 1

Given :- Length of the chord AB = 16 cm and radius (r) = 10 cm .

To find :- OM

Construction :- Draw a perpendicular OM from centre O such that, it bisects the chord AB.

Proof :- In right angled ∆OMB,

OB² = OM² + BM²

=> 10² = OM² + 8²

=> 100 = OM² + 64

=> OM² = $\sqrt{36}$

=> OM = 36

=> OM = 6 cm

Hence, the distance of the chord from the centre of the circle is 6 cm.

Amannnscharlie

Answer 2

Radius of circle is 10 cm. There are two chords of length 16 cm. What will be the distance of these chords from the centre of the circle​?