Radius of circle is 10cm distance of chord from centre is 24cm. find the length of chord
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Answered by
0
Answer:
8 cm
R.E.F image
Given OA=OB=10CM
AB=12CM
In △ OAC
(OA)2=(OC2)+(AC)2
(10)2=(OC)2+(OC)2+(6)2
(OC)2=100−36
(OC)2=64
[OC=8CM]
∴[ length of OC=8cm.]
Answered by
0
Answer:
Answer
Length of chord AB =24cm
The distance of chord AB from centre =10cm
We know that line joining the centre of the circle to the chord is perpendicular to the chord.
Therefore, in the above figure OC⊥AB
Applying Pythagoras theorem in triangle AOC we get,
AO 2 =OC
2
+AC
2
, where
AC=
2
24
=12cm and OC=10cm
Then,
AO
2
=12
2
+10
2
AO 2 =144+100
AO= 155 cm
hope it helps u
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