Question

Radius of circle is 10cm, find distance of chord from the centre if length of chord is 12 cm.​

Answer 1

The end of the chord that touches the circle when connected to the radius (o) forms an isosceles ∆

let the chord be ab

Also a perpendicular line (d) drawn to a chord ab bisects the chord into two equal parts

ab/2= 12cm/2= 6cm

in ∆ odb,

ob²= od²+db²

(10cm)²= od²+(6cm)² (ob is the radius)

od²= 100cm²-36cm²

od= √64cm²

= 8cm