Radius of circle is 10cm there are two chords of length 16cm each What will be the distance of these chords from the centre
Answers
Answered by
60
Hii There!!!
Given :- Length of the chord AB = 16cm and radius ( r ) = 10cm .
To find :- OM
Construction :- Draw a perpendicularOM from centre O such that, it bisects the chord AB.
Proof :- In right angled ∆OMB,
OB^2 = OM^2 + BM^2
=> 10^2 = OM^2 + 8^2
=> 100 = OM^2 + 64
=> OM^2 = 36
=> OM = √36
=> OM = 6 cm
Hence, the distance of the chord from the centre of the circle is 6cm.
__________________________
Hope it helps☺
# ¢ #
Given :- Length of the chord AB = 16cm and radius ( r ) = 10cm .
To find :- OM
Construction :- Draw a perpendicularOM from centre O such that, it bisects the chord AB.
Proof :- In right angled ∆OMB,
OB^2 = OM^2 + BM^2
=> 10^2 = OM^2 + 8^2
=> 100 = OM^2 + 64
=> OM^2 = 36
=> OM = √36
=> OM = 6 cm
Hence, the distance of the chord from the centre of the circle is 6cm.
__________________________
Hope it helps☺
# ¢ #
Attachments:
Answered by
47
Hii There!!!
See the above attachment......
________________
☺️====$miley=====☺️
See the above attachment......
________________
☺️====$miley=====☺️
Attachments:
Similar questions
Biology,
7 months ago
English,
7 months ago
Math,
7 months ago
Science,
1 year ago
Social Sciences,
1 year ago