Radius of circle is 13cm. There are two chords of length 24 cm each. What will be the distant of these chords from the centre of the circle
Answers
Answered by
2
Answer:
GIVEN: A circle with centre O, Radius AO = 13 cm, Chord AB = 24 cm
TO FIND : The perpendicular distance of the chord from O. Let it be called OM.
Step-by-step explanation:
OM is perpendicular to the chord AB.
Perpendicular from the centre O to a chord bisects the chord. So AM = AB/2 = 12 cm
In right triangle AMO , Using Pythagoras’s Theorem,
AO² = AM² + OM²
=> 13² = 12² + OM²
=> 169 = 144 + OM²
=> OM² = 169 - 144 = 25
=> OM = √25 = 5 cm.
Similar questions