Question

radius of circle is 5 cm . the length of a chord of the circle is 8 cm .find the distance of the chord the center​

Answer 1

Step-by-step explanation:

From Pythagoras theorem,

x^2=25-16

x=9

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Answer 2

Answer:

The distance from center and chord = 3 cm

Step-by-step explanation:

See the attached figure.

OB is the radius = 5cm.

AB is the chord. Where OD is the distance between Center and the chord.

Also, OD is perpendicular to AB and bisects AB.

Therefore, AD = DB = 4 cm.

Let's calculate OD using Pythagoras theorem -

   OD² + DB² = OB²

⇒ OD² + 4² = 5²

⇒ OD² + 16 = 25

⇒ OD² = 25 - 16

⇒ OD² = 9

⇒ OD = 3 cm

Hence, the distance from center and chord = 3 cm