Question

Radius of circumcircle of a triangle ABC is5/10 units. If point P is equidistant from A(1,3),B(-3,5) and C(5, -1), then find AP.ANSWER THIS QUESTION THEN I WILL MARK THEM AS BRAINLISTPLEASE ANSWER MY QUESTIONS...​

Answer 1

The distance AP is 1/2 units

Step-by-step explanation:

If the radius of the circumcircle of the triangle is 5/10 i.e. 1/2 units

And P is a point that is equidistance from vertices A, B and C of the triangle ABC then

P will be the circumcentre

Thus, AP will be nothing but the radius of the circumcircle

Therefore, the distance AP will be 1/2 units or 0.5 units

Hope this answer is helpful to you.

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Answer 2

Answer:

I know till here is the correct explanation