Radius of circural base of an ear of corn is 6.6cm and its length is 11.2cm.If an avg 1sqcm area contains 2 corn kernels,find the total number of kernels on a corn
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Answered by
6
Hello Mate!
Here is your solution!
Curved surface area of corn = πrl
Now, l = √( r² + h² )
= √( 6.6² + 11.2² )
= √( 43.56 + 125.44 )
= √169 = 13 cm
So, curved surface area = 22/7 × 6.6 × 13 cm²
= 269.7 cm²
Now, when 1 cm² covers = 2 kernels
Then 269.7 cm² will cover = 269.7 × 2 = 539.4 kernels
Hence, 539 kernels ( approx. ) will be in the corn.
Have great future ahead!
Here is your solution!
Curved surface area of corn = πrl
Now, l = √( r² + h² )
= √( 6.6² + 11.2² )
= √( 43.56 + 125.44 )
= √169 = 13 cm
So, curved surface area = 22/7 × 6.6 × 13 cm²
= 269.7 cm²
Now, when 1 cm² covers = 2 kernels
Then 269.7 cm² will cover = 269.7 × 2 = 539.4 kernels
Hence, 539 kernels ( approx. ) will be in the corn.
Have great future ahead!
snehdeep93:
thanks
Answered by
5
हल -
दिया है -
शंकु की ऊंचाई h = 11.2
त्रिज्या r = 6.6
अतः तिर्यक् ऊँचाई l = √(r² + h²)


शंकु का वक्र पृष्ठ = πrl


जब 1cm² = 2 kernels को ढक लेता है तो,
269.7cm² ढकेगा 539.4 kernels को
दिया है -
शंकु की ऊंचाई h = 11.2
त्रिज्या r = 6.6
अतः तिर्यक् ऊँचाई l = √(r² + h²)
शंकु का वक्र पृष्ठ = πrl
जब 1cm² = 2 kernels को ढक लेता है तो,
269.7cm² ढकेगा 539.4 kernels को
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