Radius of cross section of a solid right circular cylindrical rod is 3.2 dm. The rod is melted and 44 equal solid cubes of side 8 cm are formed. The length of the rod is (Take Π = 22/7)
A) 56 cm B) 7 cm C) 5.6 cm D) 0.7 cm
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Answer:
your answer is A 56 cm please follow me
Answered by
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Answer:
B)7 cm
Step-by-step explanation:
Given,
radius=3.2dm
1dm=10cm
3.2 dm=32cm
r=32cm
volume of cylinder is π*r^2*h
The rod is melted and 44 equal solid cubes of side 8 cm are formed
volume of cube is a^3
here a=8
so,
22/7*32*32*h=44*8*8*8
h=7cm
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