Question

Radius of current carrying coil is 'R'. Then ratio
of magnetic fields at the centre of the coil to the
axial point, which is R√3 distance away from the
centre of the coil :-
(1) 1 : 1 (2) 1 : 2 (3) 1 : 4 (4) 8 : 1​

Answer 1

Answer:

• In the given question we have to find magnetic field to the centre of the coil, which is at

$r \sqrt{3}$

• As we know magnetic field at the centre equal to = [ B ° / r ]........... (1)
• Hence, using formula of B axial

B axial =

[B°] / $( \: r{}^{2} + x {}^{2}) \frac{3}{2}$

Putting the values we get,

[ B°] / $(\: r{}^{2} + r \sqrt{3} {}^{2}) \frac{3}{2}$

B° / $(\: r{}^{2} + r \sqrt{3} {}^{2}) {}^{3}{} \frac{}{2}$

B° / $(4r {}^{2}) {}^{3} \frac{}{2}$

B ° / (2r)^2*3/2

• Hence B axial = B° / 8r........... (2)

On diving equation (2) to (1)

[ B° / 8r ] ÷ [B °/ r ]

We get, 8:1 is the correct answer

Answer 2

Answer:

see attachment

Explanation:

hope it helps you..