Physics, asked by Kdinga3262, 11 months ago

Radius of curvature is 20 cm then power in biconvex lens is

Answers

Answered by sugar1110
1
R=2f
f=R/2
=20/2
=10cm
1m=100cm
10cm=0.1m
P=1/f
=1/0.1
=10D
Answered by Anonymous
0

HOLA MATE !!!

HOPE THIS HELPS YOU ...


Formulas:

We know that ,

1) Radius of curvature = 2 * Focal length

or R = 2f

2) Power = 1/focal length

or P = 1/f


Given Data :

R = 20cm


Step-by-Step Explanation :

R = 2f

=> f = 10cm = 0.1m

P = 1/f

=> P = 1/0.1

=> P = 10 D

Hence power of the lens is 10 D





THANK YOU FOR THE WONDERFUL QUESTION ...

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