Physics, asked by varshaa2002soni, 10 months ago

radius of curvature of concave lens, is
(a) R = (LxL)/6h + h/2
(b) R = L/6h + h/2

Answers

Answered by bhapriyanka3
0

Explanation:

Given, l=3cm,Δl=0.1cm,h=0.045cm,Δh=0.005cm

Now, R=

6h

l

2

+

2

h

Take ln and differentiate (only be taken magnitude)

so, relative error ,

R

ΔR

=2

l

Δl

+

h

Δh

+

h

Δh

=2

3

0.1

+2

0.045

0.005

=0.3

use like this method

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