radius of curvature of concave lens, is
(a) R = (LxL)/6h + h/2
(b) R = L/6h + h/2
Answers
Answered by
0
Explanation:
Given, l=3cm,Δl=0.1cm,h=0.045cm,Δh=0.005cm
Now, R=
6h
l
2
+
2
h
Take ln and differentiate (only be taken magnitude)
so, relative error ,
R
ΔR
=2
l
Δl
+
h
Δh
+
h
Δh
=2
3
0.1
+2
0.045
0.005
=0.3
use like this method
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