Question

Radius of dees of a 10^7 hz cyclotron is 0.6m. Find the operating magnetic field and the kinetic energy of proton beam produce by it.

Answer 1

Answer:

=V=10MHz 10=Hz

B=?

V=2πMBq

or B=q2πMV

=1.6×10−192×(722)×(1.67×10−27)107

=0.656T

Now,

Emax=2MB2q2R2=2×1.67×10−27(0.656)2×(1.67×10−27)2×(60×10−2)2

=1.19×10−12J

=1.6×10−19×1061.19×10−12

=7.421mev