Question

Radius of Earth is around 6000 km.What will be the weight of a body at height of 6000 km from Earth surface?

Answer 1

Explanation:

The value of g at a height h from the surface of the Earth =>

$\frac{g}{ {(1 + \frac{h}{r}) }^{2} }$

It is given that the body is at height of 6000 km from Earth's surface. Hence the value of g at height h from Earth's surface =

$\frac{g}{ {(1 + 1)}^{2} } = \frac{g}{4}$

So the weight of the body becomes one-fourth of the original weight. Hope it helps you.