Question

radius of eqn of circle--x²+y²-14x-10y-151=0 is?​

Answer 1

Answer:

x²+y²+2gx+2fy+c=0

2g=-14

g=-7,

2f=-10

f=5

radius=√(g²+f²-c)

r=√(49+25+151=√225=15 unit

Answer 2

Step-by-step explanation:

x²+y²-14x-10y-151=0

g = -7 and f = -5

(h,k)=centre= (7,5)

r= √ h^2 + k^2 - c

r = √49 + 25 -(-151)

r = √ 74+151

r = √ 225

r = 15

Hope it helps you!