Question

Radius of
gyration of a body about an axis at a
distance 0.12m, from its centre of mass in 0.13 m.
find
the radius of gyreation about a parallel axis
passing through the centre of mass​

Answer 1

Answer:

071 is the answer I think soo not sure

Answer 2

Given :

• Radius of gyration (K) = 0.13 m
• Distance of the parallel axis from the COM (d)= 0.12 m

Solution :

Moment of inertia of the body about a parallel axis passing through the COM

⇒ I ꜀ₘ = MK꜀ₘ²

The moment of inertia of the body about the given axis ,

⇒ I = MK²

According to parallel axis theorem ,

⇒ I = I ꜀ₘ + Md²

⇒ MK² =  MK꜀ₘ² + Md²

Hence ,

⇒ K² = K꜀ₘ² + d ²

⇒ K꜀ₘ² = K² - d²

⇒ K꜀ₘ² =( 0.13)² - (0.12)²

⇒ K꜀ₘ² = (0.13 - 0.12 )(0.13 +0.12)

⇒ K꜀ₘ² = 0.01 x 0.25

⇒ K꜀ₘ² = 0.0025

⇒ K꜀ₘ = 0.05 m

The radius of gyration about a parallel axis passing through the COM is 0.05 m.