Question

Radius of hydrogen atom in the ground state is 0.53angstrom the radius of liplus 2 ion in a similar state is

Answer 1

Answer:

0.17 Angstroms

Explanation:

We know that,

$r \propto n^2$

$r \propto \dfrac {1}{Z}$

Given that,

Radius of hydrogen atom in the ground state is 0.53 Angstroms

Here,

n = 1

Z = 1

So,

r = 0.53 Angstroms

We should find for $Li^{2+}$

So, for Li 2+

n = 1

Z = 3

Therefore, Substituting

r = 0.53 x 1/3

Hence,

r = 0.17 Angstroms

Answer 2

Explanation:

question:

Radius of hydrogen atom in the ground state is 0.53angstrom the radius of liplus 2 ion in a similar state is

Answer:

State of hydrogen atom (n) = 1(due to ground state).

Radius of hydrogen atom (r) = 0.53 Å.

Atomic number of Li (Z) = 3.

Radius of Li2+ ion = r x n²/Z = 0.53 x 1²/3 = 0.17