Radius of hydrogen's third atomic radius
Answers
Answered by
0
Here, r =? n = 3, E =?
As r = n2h2/4∏2 mke2
r = 9 × (6.6 × 10-34)2 × 9 × 109/ [4 × (22/7) × (22/7) × 9.1 × 10-31 (1.6 × 10-19)2
= 4.775 × 10-10 m
= 4.775 Å
E = - 2∏2 mk2 e4/n2h2
On putting the standard values, we get
E = - 2.43 × 10-19 J
As r = n2h2/4∏2 mke2
r = 9 × (6.6 × 10-34)2 × 9 × 109/ [4 × (22/7) × (22/7) × 9.1 × 10-31 (1.6 × 10-19)2
= 4.775 × 10-10 m
= 4.775 Å
E = - 2∏2 mk2 e4/n2h2
On putting the standard values, we get
E = - 2.43 × 10-19 J
Similar questions