Question

Radius of one arm of hydraulic lift is four times of radius of other arm what force should be applied on the narrow to lift 100kg

Answer 1

Answer:

Step-by-step explanation:

F1/A1=F2/A2

F1/πr^2=100×g/π(4r)^2

16πr^2/πr^2=100×g/F1

16F1=100×g

F1=100×g/16 where g is given gravity

Answer 2

Dear Student,

◆ Answer -

Force applied at narrow arm = 61.25 N

● Explanation -

Force acting at 100 kg wt = 100 × 9.8 = 980 N.

Using Pascal's principle -

F1/F2 = A1/A2

980/F2 = πr1^2 / πr2^2

980/F2 = (r1/r2)^2

980/F2 = 4^2

F2 = 980 / 16

F2 = 61.25 N

Hence, 61.25 N of force is applied to the narrow arm.

Thanks dear. Hope this helps you...