radius of shere is 5cm and it is increased by 20%.fimd ratio od T.S.A in two cases
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Answer = 36 : 25
Step-by-step explanation =
Total Surface Area of sphere = 4πr²
Orginal T.S.A = 4π(5)²
Original T.S.A = 100π
Now, radius has been increased by 20%,
= 5 cm + ( 5 × 20/100 )
= 5 cm + 1 cm = 6 cm
New T.S.A = 4π(6)²
New T.S.A = 144π
New T.S.A / Original T.S.A = 144π / 100π
= 72/50 = 36/25
= 36 : 25
Step-by-step explanation =
Total Surface Area of sphere = 4πr²
Orginal T.S.A = 4π(5)²
Original T.S.A = 100π
Now, radius has been increased by 20%,
= 5 cm + ( 5 × 20/100 )
= 5 cm + 1 cm = 6 cm
New T.S.A = 4π(6)²
New T.S.A = 144π
New T.S.A / Original T.S.A = 144π / 100π
= 72/50 = 36/25
= 36 : 25
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