Radius of smaller piston and larger piston of a hydraulic
lift are 5 cm and 15 cm respectively. How much force is
required on the smaller piston to lift a car of 1500 kg
weight ? Find the upward pressure acting on the smaller
piston in this condition.
Answers
Answered by
3
Explanation:
g =10 m/s^2
suffix 1 indicates smaller, 2 for larger piston
as per Pascal's law
F1/ A1 = F2/A2
F1 = 1500*10*π*5^2/(π*15^2)
= 1500*10/9 = 1666.67 N
pressure = Force /area
= 1666.67/(π*25*10^-4)
= 21.22*10^4 N/m^2
Similar questions