Physics, asked by ashiki26, 1 year ago

Radius of smaller piston and larger piston of a hydraulic
lift are 5 cm and 15 cm respectively. How much force is
required on the smaller piston to lift a car of 1500 kg
weight ? Find the upward pressure acting on the smaller
piston in this condition.​

Answers

Answered by ferozemulani
3

Explanation:

g =10 m/s^2

suffix 1 indicates smaller, 2 for larger piston

as per Pascal's law

F1/ A1 = F2/A2

F1 = 1500*10*π*5^2/(π*15^2)

= 1500*10/9 = 1666.67 N

pressure = Force /area

= 1666.67/(π*25*10^-4)

= 21.22*10^4 N/m^2

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