Question

Radius of sphere with +20q charge is R/4 and radius of sphere with -6q charge has radius R. They are connected and then released. ​

Answer 1

Answer:

2.8q and 11.2q

Explanation:

since potential is proportional to Q/R.

and total charge available is 20-6=14q.

let this be split into x and 14-x onto spheres of radius R/4 and R.

for equipotential of the spheres, since they touched, x/(R/4) = 14-x/R

4x = 14-x

5x=14

x=14/5=2.8

14-x=11.2