Question

Radius of taps folwing in a tank are2cm,4cm,5/3cm. Smallest tap fill the tank in 144min.If water flowing from the tap is directly proportional to the square of radius of tap.Then how much time required to completely fill the tank?​

Answer 1

Time taken to fill the tank by the tap having 2 cm diameter = 61 min∴ Time taken to fill the tank by the tap having 1 cm diameter= 61 x (2/1)2 = 244 minSimilarly, time taken to fill the tank by the tap having 4/3 cm diameter= 61 x [(2 x 3)/4]2 = 61 x 9/4 = 549/4 min.∴ Part of the tank filled by all the three pipes in 1 min= 1/61 + 1/244 + 1/(549/4)= (36 + 9 + 16)/2196 = 61/2196 = 1/36Hence, required time taken = 36 min