Radius of the base of a cylindrical water drum open at the top is 35 CM and height 1.3m .Find the inner surface area of the water drum.
Answers
Answered by
17
Hello...
Answer...
radius = r = 35cm
height = h = 1.3m = 130 cm
Inner surface area of water drum
= curved surface area + base area
= 2πrh + πr²
= πr (2h + r )
= 22/7×35×(2×130+35) cm²
= 32450cm²
Hope it helped.
☺☺☺☺☺
Answer...
radius = r = 35cm
height = h = 1.3m = 130 cm
Inner surface area of water drum
= curved surface area + base area
= 2πrh + πr²
= πr (2h + r )
= 22/7×35×(2×130+35) cm²
= 32450cm²
Hope it helped.
☺☺☺☺☺
Answered by
13
Radius of Base = 35 cm
Height = 1.3 m = 130 cm
Inner Surface Area = Curved Surface Area + Area of base
= 2 pi r h + pi r^2
= 2 × 22 × 35 × 130 / 7 + 22 × 35× 35 / 7
= 2 × 22× 5 × 130 + 22× 5 × 35 cm^2
= 220 × 130 + 110 × 35 cm^2
= 28600 + 3850 cm^2
= 32450 cm^2
Height = 1.3 m = 130 cm
Inner Surface Area = Curved Surface Area + Area of base
= 2 pi r h + pi r^2
= 2 × 22 × 35 × 130 / 7 + 22 × 35× 35 / 7
= 2 × 22× 5 × 130 + 22× 5 × 35 cm^2
= 220 × 130 + 110 × 35 cm^2
= 28600 + 3850 cm^2
= 32450 cm^2
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