Question

Radius of the base of a Right circular cyclinder is 14 dm and height is 15cm
Find the -
1) Curved surface of the cyclinder
2) total surface area of the cyclinder​

Answer 1

Answer:

14dm = 14/10cm

hight = 15cm

Step-by-step explanation:

formula = 2πrh

22/7 × 14/10cm × 15

=132cm^2

2πr(r+h)

2×22/7 × 14/10 (14/10 + 15)

44 × 0.2 (164/10)

8.8 (16.4)

144.32 cm^2

Answer 2

Given :-  

• Radius of the cylinder is 14 dm  
• Height of the cylinder is 15 cm  

To Find :-  

• Curved surface area of the cylinder ( CSA )
• Total Surface area of the cylinder ( TSA )

Solution :-  

~ Here , radius of the cylinder is given in dm so we’ll convert it into cm first  

→ 1 dm = 10 cm  

→ 14 dm = 14 × 10 = 140 cm  

____________

⇒  Finding the curved surface area :-  

${\boxed{\underline{\red{ CSA = 2\pi rh}}}$

$\sf \implies 2 \times \dfrac{22}{7} \times 140 \times 15$

$\sf \implies 2 \times 22 \times 20 \times 15$

$\sf \implies 13200$

____________

⇒ Finding the total surface area :-  

${\boxed{\underline{\red{TSA = 2 \pi r ( h + r ) }}}$

$\sf \implies 2 \times \dfrac{22}{7} \times 140 \times ( 15 + 140 )$

$\sf \implies 2 \times 22 \times 20 \times 155$

$\sf \implies 136400$

____________

More about Cylinder :-

$\sf \implies C.S.A = 2\pi rh$

$\sf \implies T.S.A = 2\pi r ( h + r )$

$\sf \implies Volume = \pi r^{2}h$

____________