Question

radius of the base of a right circular cylinder is halved and the height is doubled what is the ratio of the volume of the new cylinder to that the original cylinder​

Answer 1

For a right circular cylinder ,

V =

$v = \pi {r}^{2} h$

$v1 = \pi \times {r}^{2} \times h \\ \\ v2 = \pi ({r}^{2} \div 4) \times 2h$

Hence ,

Ratio of the new to the old is 1:2.

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Answer 2

Answer:

radius of original cylinder=r

height of original cylinder=h

radius of new cylinder=1/2r

height of new cylinder=2h

volume of cylinder=πr^2h

volume of original cylinder/volume of new cylinder

=πr^2h/π1/2r^2×2h

=r^2h/1/4r^2×2h

=r^2h/4/2r^2h

=2/4

=2:4