Radius of the circle 2x^2+2y^2-x=0
(a) (1/4,0)
(b) (-1/2,0)
(c) (-1,0)
(d) (1,0)
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Answered by
1
Step-by-step explanation:
Radius of the circle 2x^2+2y^2-x=0
(a) (1/4,0)
(b) (-1/2,0)
(c) (-1,0)
(d) (1
answer is a ,0)
Answered by
0
hope it's helpful dear friend..
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