Math, asked by czwpsqz811, 4 months ago

Radius of the circle 2x^2+2y^2-x=0
(a) (1/4,0)
(b) (-1/2,0)
(c) (-1,0)
(d) (1,0)​

Answers

Answered by rashmikerketta1981
1

Step-by-step explanation:

Radius of the circle 2x^2+2y^2-x=0

(a) (1/4,0)

(b) (-1/2,0)

(c) (-1,0)

(d) (1

answer is a ,0)

Answered by Anonymous
0

hope it's helpful dear friend..

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