Question

Radius of the circle 2x2+2y2+8x+4y-3=0 is

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Answer 1

Answer:

$\sqrt{7 }$

Answer 2

Answer:

2x2+2y2+8x+4y-3=0

4+2y2+8x+4y-3=0

1+2y2+8x+4y=0

2y2+8x+4y=-1

4y+4y+8x=-1

8y+8x=-1

8(x+y)=-1

x+y=-1/8