radius of the circle is 10.5 cm and angle of the sector is 45 degree find the area of minor sector of circle
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Answered by
5
ANSWER:
area of a circle = πr²
so, for 360°
area = πr²
so, for 45°
area = πr²/8
Hence, the area of the minor segment is 43.325 cm².
Answered by
27
Answer:
⇒ 43.3125 cm²
Step-by-step explanation:
Given,
Radius of the Circle = 10.5 cm
Angle of the sector = 45°
To find,
The area of minor sector of circle.
We know that:
Area of circle = πr²
Therefore, for 360° the area would be πr².
And, for 45° the area would be:
⇒ 360/45 = 8
∴ πr²/8
So,
⇒ 22 × 10.5 × 10.5/ 7 × 8
⇒ 2,425.5 / 56
⇒ 43.3125 cm²
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