Question

radius of the circle is 10.5 cm and angle of the sector is 45 degree find the area of minor sector of circle​

Answer 1

ANSWER:

area of a circle = πr²

so, for 360°

area = πr²

so, for 45°

area = πr²/8

$area \: = \frac{\pi {r}^{2} }{8} \\a rea = \frac{22 \times 10.5 \times 10.5}{7 \times 8} \\ area = 43.325 \: {cm}^{2}$

Hence, the area of the minor segment is 43.325 cm².

Answer 2

Answer:

⇒ 43.3125 cm²

Step-by-step explanation:

Given,

Radius of the Circle = 10.5 cm

Angle of the sector = 45°

To find,

The area of minor sector of circle.

We know that:

Area of circle = πr²

Therefore, for 360° the area would be πr².

And, for 45° the area would be:

⇒ 360/45 = 8

∴ πr²/8

So,

⇒ 22 × 10.5 × 10.5/ 7 × 8

⇒ 2,425.5 / 56

⇒ 43.3125 cm²