Question

Radius of the circle is 13cm om=on=op=5cm . Find the perimeter of the triangle.​

Answer 1

Answer:

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Step-by-step explanation:

15 cm is wrong

Answer 2

Given: Two tangents are drawn from an external point A to the circle with centre O. Tangent BC is drawn at a point R and radius of circle = 5 cm.

Find : Perimeter of ∆ABC.

Proof: We know that,

∠OPA = 90° [Tangent at any point of a circle is perpendicular to the radius through the point of contact]

OA² = OP² + PA² [by Pythagoras Theorem]

(13)² = 5² + PA² ⇒ PA² = 144 = 12²

⇒ PA = 12 cm

Now, perimeter of ∆ABC = AB + BC + CA = (AB + BR) + (RC + CA) = AB + BP + CQ + CA

[BR = BP, RC = CQ tangents from internal point to a circle are equal]

= AP + AQ = 2AP = 2 x (12)

= 24 cm

[AP = AQ tangent from internal point to a circle are equal]

Therefore, the perimeter of ∆ABC = 24 cm.

I hope it's help for you ☺️