Radius of the circle touching the lines 3x + 41-14= 0 and 6x+81 - 7=0 is
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Answer:3x+4y-14=0=>eqn (1)
6x+8y+7=0=>eqn (2)
Eqn (2) divide with 2
Then lines are parallel
3x+4y=14,3x+4y=-7/2
Radius= 1/2 × distance b/w lines
=1/2×14+7/2/√3^2+4^2
The final answer is 7/4
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