Question

Radius of the circular sheet= 14cm

Area= \pi r^2=\frac{22}{7}\times14\times14cm^2πr
2
=
7
22
​
×14×14cm
2


=616cm^2=616cm
2


Area of 2 small circles= 2\pi r^2πr
2


=2\times\frac{22}{7}\times3.5\times3.5cm^2=2×
7
22
​
×3.5×3.5cm
2


=77.0cm^2=77.0cm
2


Area of the rectangle= l\times bl×b

=3\times1cm^2=3cm^2=3×1cm
2
=3cm
2


Area of the remaining sheet after removing the 2 circles and 1 rectangle

=616cm^2-\ \left(77+3\right)cm^2=616cm
2
− (77+3)cm
2


=616cm^2-\ 80cm^2=536cm^2=616cm
2
− 80cm
2
=536cm
2

Answer 1

Step-by-step explanation:

Radius of the circular sheet= 14cm

Area= \pi r^2=\frac{22}{7}\times14\times14cm^2πr

2

=

7

22

×14×14cm

2

=616cm^2=616cm

2

Area of 2 small circles= 2\pi r^2πr

2

=2\times\frac{22}{7}\times3.5\times3.5cm^2=2×

7

22

×3.5×3.5cm

2

=77.0cm^2=77.0cm

2

Area of the rectangle= l\times bl×b

=3\times1cm^2=3cm^2=3×1cm

2

=3cm

2

Area of the remaining sheet after removing the 2 circles and 1 rectangle

=616cm^2-\ \left(77+3\right)cm^2=616cm

2

− (77+3)cm

2

=616cm^2-\ 80cm^2=536cm^2=616cm

2

− 80cm

2

=536cm

2