Question

Radius of the earth is 6400 km.What will be weight of 100kg.If it is taken to a height of 2000 km above the earth surface.

Answer 1

Given ;

• r = 6400 km = 6400000m = 6.4 × 10^6
• h = 2000km = 2000000m = 2 × 10^6

• Thus total h from the centre = 6400000 + 200000 = 8.4 × 10^6m

• mass of the object = 100kg

Thus weight of the object = mg = F = GMm/r²

Thus weight = force of attraction experienced:

• F = GMm/r²
• F = 6.67 × 10^-11 × M(Earth) × M(object) / r²
• F = 6.67 × 10-11 × 6 × 10²⁴ × 10² / 8.4 × 10^6
• F = 6.67 × 10^-11 × 6 × 10²⁴ × 10^-4 / 8.4
• F = 6.67 × 10^-11 × 6 × 10^20 / 8.4
• F = 4.76 × 10^9 N = W

#answerwithquality

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Answer 2

Explanation:

By the Newton's law of gravitation,

$F = \frac{GMm}{ {(r + h)}^{2} }$

in which the force is nothing but the force exerted on body by earth's gravitational attraction is weight

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