Question

radius of the earth is approximately 6400km. suppose,a rope is wound around the equator touching the surface of the earth, and another such that it is at a distance of 160 m from the surface at all points and find the difference in the lengths of the two ropes.[ take π= 3.14]​

Answer 1

Step-by-step explanation:

The rope forms a perfect circle around the Earth. Therefore, its initial circumference is equal to 2πr. If we add 1 meter, it becomes 2πr+1. The way that we can find the new radius with this as its diameter is through basic algebra:

Let us find the new radius, which we will denote with s.

2πs = 2πr+1.

Dividing each side by 2π, we get:

s = (2πr+1)/2π

We want to solve for the difference between r and s. In other words:

s-r = (2πr+1)/2π - r

Plugging in r = 6400, we get that the difference is approximately 0.159 m.