Radius of the fourth orbit in hydrogen atom is 8.5×10^-10m. calculate the velocity of electron in this Orbit .
Given m= 9.1×10^-31kg.
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please refer to attchment
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Answer:
- 5.5 × 10^5m/s
Explanation:
- As we know that For hydrogen z = 1
- Formula Vn = 2πke²/nh
- Where, k = 9×10^9 jm/c²
- h = 6.62×10^-34js
- e = 1.6 × 10^-19 c
- n = 4
Now , V4 = 2× 3.14 × 9× 10^9 × (1.6× 10^-19c)²/ 4× ( 6.62 × 10^-34)²
V4 = 144.69 × 10 ^-24 /26.05× 10^-34
V4 = 5.5 × 10 ^5 m/s Answer ✔
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