Radius of the second bhor orbit for hydrogen atom
Answers
Answered by
1
Answer:
clearly
Rn=n^2h^2/4pie^2me^2
=Ron^2/z
= 52.9×4/1
= 211.6 pm
Answered by
1
Answer:
Bohr's radius = 0.529 × n^2/Z
= 0.529 × 2^2/1
= 2.116 A°
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