radius of two circles are 5m and 12m. find the diameter of the circle whose area is equal to the sum of areas of the two circle
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Area Of Circle A + Area of Circle B = Area of Circle C
πr² + πR² = Area Of Circle C
22/7 × 5 × 5 + 22/7 × 12 × 12 = area of C
78.5714285714 + 452.5714285714 = area of C
531.1428571428 = area Of C
531.1428571428 = πr²
531.1428571428 = 22/7 × r²
531.1428571428 × 7/22 = r²
169 = r²
√169 = r
13= r
d = 26
πr² + πR² = Area Of Circle C
22/7 × 5 × 5 + 22/7 × 12 × 12 = area of C
78.5714285714 + 452.5714285714 = area of C
531.1428571428 = area Of C
531.1428571428 = πr²
531.1428571428 = 22/7 × r²
531.1428571428 × 7/22 = r²
169 = r²
√169 = r
13= r
d = 26
Sheshank333:
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i don't know
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which class do you study??
8th
me too
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area of circle a +area of circle b
= πr^2+πR^2
=π{r^2+R^2}
= π{5^2+12^2}
= π{25+144}
=π×169
= 22/7×169
22×24.14(aprox)
= 48.28+482.80
= 531.08
area of big circle =πr^2=531.08
πr=531.08/2
πr=265.54
r=265.54×7/22
r=12.7×7
r= 88.9
therefore
d=r^2=88.9×88.9
= πr^2+πR^2
=π{r^2+R^2}
= π{5^2+12^2}
= π{25+144}
=π×169
= 22/7×169
22×24.14(aprox)
= 48.28+482.80
= 531.08
area of big circle =πr^2=531.08
πr=531.08/2
πr=265.54
r=265.54×7/22
r=12.7×7
r= 88.9
therefore
d=r^2=88.9×88.9
sorry but i could not understand ur answer
but thanks
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