Question

Radius of two circles R and r touching externally ,PQ is length of a direct common tangent .
distance between the centres is d .
Show that,
PQ² = d² - (R-r)²
​

Answer 1

(Alt )^2 = ( hyp)^2 -(base )^2

PQ^2= d^2 - ( R-r )^2

Hope it helps you a little.

Answer 2

Answer:

Step-by-step explanation:

Given R and r two circles

and pQ is a length

To prove:-

PQ² = d² - (R-r)²

Solution:-

H^2=b^2+p^2

P^2=h^2-b^2

PQ^2= d^2 - ( R-r )^2

Hp

Hope it helps you