Question

Radius of two different orbits in a H like sample is 4r and 16r respectively. What is the ratio of the frequency of revolution of electron in these two orbits

Answer 1

Given:

Number of orbits = 2

Radius = r1 = 4r

Radius = r2 = 16r

To Find:

The ratio of the frequency of revolution of an electron in two orbits

Solution:

The Relation between radius and frequency for an electron in an orbit is -

V = v/2πT

Therefore, the ratio is -

v1/v2 = v/2π4r/v/2π16R

= 4/1

= 4:1

Answer: Thus, the ratio of electron in these two orbits is 4:1