radius ratio of KF is 0.98 the structure of f is of type a) NaCl(b)
ZnS (c)CsCl
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Given:
The radius ratio of KF is 0.98.
To find:
The structure of KF solid
Solution:
Since the radius ratio for KF is: 0.98
⇒ 0.732 ≤ radius ratio of KF ≤ 1
Therefore, the cations would occupy the cubical voids, and hence according to the radius ratio rule: the compound will have cubic structure.
We know, the structure of the following compounds :
- CsCl: cubic
- NaCl: octahedral
- ZnS: tetrahedral
Answer:
The structure of KF is: cubic, similar to CsCl, hence the answer is: (c) CsCl
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