Question

Raghav bought a second-hand car for 95000
After using the car for two years, he sold it out
The cost of the car depreciated by 20% in the
first year and by 15% in the second year. What
amount did Raghav get for the car?​

Answer 1

AnswEr :

$\bold{Given} \begin{cases}\sf{Cost \: Price \: (CP)=Rs.95000} \\ \sf{Deprecation \: (D_1)=20\%}\\ \sf{Depreciation \: (D_2)=15 \%}\\ \sf{Selling\:Price\:(SP)=?}\end{cases}$

• Let's Head to the Question Now :

$\longrightarrow \sf SP = CP \times (100 - D_1)\% \times (100 - D_2)\%$

$\longrightarrow \sf SP = 95000 \times (100 - 20)\% \times (100 - 15)\%$

$\longrightarrow \sf SP = 95000 \times 80\% \times 85\%$

$\longrightarrow \sf SP = 950\cancel{00} \times \cancel\dfrac{80}{100} \times \dfrac{85}{\cancel{100}}$

$\longrightarrow \sf SP = 950\times \dfrac{4}{\cancel5}\times\cancel{85}$

$\longrightarrow \sf SP =Rs. \: ( 950 \times 4 \times 17)$

$\longrightarrow \boxed{ \sf SP =Rs. \:64600}$

⠀

∴ Raghav will get Rs. 64,600 for car.

Answer 2

Answer:

64600

Step-by-step explanation:

first year

95,000 - Percentage decrease =

95,000 - (20% × 95,000) =

95,000 - 20% × 95,000 =

(1 - 20%) × 95,000 =

(100% - 20%) × 95,000 =

80% × 95,000 =

80 ÷ 100 × 95,000 =

80 × 95,000 ÷ 100 =

7,600,000 ÷ 100 =

76,000

second year

76000 - Percentage decrease =

76000 - (15% × 76,000) =

76,000 - 15 × 76,000 =

(1 - 15%) × 76,000 =

85%  × 76,000 =

85% × 76,000 =

85 ÷ 100 × 76,000 =

85 *76,000 ÷ 100 =

6,460,0,000‬/100=

64600

he get 64600