Math, asked by genius1947, 1 month ago

Raghav invests Rs. 12,000 partly in 10% (Rs. 80) shares at Rs. 120 and partly in 5% (Rs. 100) shares at Rs. 150. If his total income is Rs. 500, then how much he invested in each?


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Answered by Luckydancer950
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Answered by mathdude500
24

\large\underline{\sf{Solution-}}

Let assume that Raghav invested in 10% (Rs. 80) shares at Rs. 120 be Rs x .

So, his investment in 5% (Rs. 100) shares at Rs. 150 be Rs 12000 - x.

Now,

Case :- 1

Face value of share = Rs 80

Dividend % = 10 %

So, Income on 1 share = 10 % of 80 = Rs 8.

Market value of 1 share = Rs 120

Investment = Rs x

So,

\rm :\longmapsto\:Income \: on \: 1 \: share \: of \: Rs \: 120 = Rs \: 8

Thus,

\rm :\longmapsto\:Income \: on \: Rs \: x = \dfrac{8}{120} \times x = Rs \: \dfrac{x}{15}

Case :- 2

Face value of share = Rs 100

Dividend % = 5 %

So, Income on 1 share = 5 % of 100 = Rs 5.

Market value of 1 share = Rs 150

Investment = Rs 12000 - x

So,

\rm :\longmapsto\:Income \: on \: 1 \: share \: of \: Rs \: 150 = Rs \: 5

Thus,

\rm :\longmapsto\:Income \: on \: Rs \: 12000 - x = \dfrac{5}{150} \times (12000 - x) = Rs \: \dfrac{(12000 - x)}{30}

Now,

According to statement,

Total annual Income = Rs 500

Thus,

\rm :\implies\:\dfrac{x}{15}  + \dfrac{12000 - x}{30}  = 500

\rm :\longmapsto\:\dfrac{2x + 12000 - x}{30}  = 500

\rm :\longmapsto\:\dfrac{x + 12000}{30}  = 500

\rm :\longmapsto\:x + 12000 = 15000

\rm :\longmapsto\:x = 15000 - 12000

\bf\implies \:x = 3000

So,

The Investment in 10% (Rs. 80) shares at Rs. 120 = Rs 3000

and

The investment in 5% (Rs. 100) shares at Rs. 150 be Rs 12000 - 3000 = Rs 9000.

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