Raghu has a box of dimensions 40cm*30cm*70cm. All the faces of the box are rectangular. if the area of its top and bottom surfaces are equal to 2100cm^2 each, what is the total area of the remaining four faces of the box?
Answers
Answered by
4
Answer:
8000 is the area of 4 walls
Step-by-step explanation:
40*30*2
ie. 2400 cm2
is the are of 2 sides of the wall
and remaining 2 sides will be
40*70*2
ie. 5600 cm2
so total area is
2400+5600
8000
Answered by
1
Answer:
8000 cm^2
Step-by-step explanation:
Total surface are of box = 2 (lb + bh + lh) = 2( 70 × 40 + 40 × 30 + 70 × 30)
= 2 (2800 + 1200 + 2100) cm^2
Area of top and bottom surface = 2 × 2100 cm2
Area of other 4 surfaces = 2 (2800 + 1200 + 2100) cm^2 - 2 × 2100 cm^2
= 2 (2800 + 1200) cm^2
= 2 × 4000 cm^2
= 8000 cm^2
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