Math, asked by vaishu4871, 8 months ago

Raghu has a box of dimensions 40cm × 30cm × 70cm. All the faces of the box are rectangular. If the area of its top and bottom surfaces are equal to 2100cm^2
each, what is the total area of the remaining four faces of the box?​

Answers

Answered by saiprasad45093067
0

Answer:

8000 cm^2

Step-by-step explanation:

Total surface are of box = 2 (lb + bh + lh) = 2( 70 × 40 + 40 × 30 + 70 × 30)

= 2 (2800 + 1200 + 2100) cm^2

Area of top and bottom surface = 2 × 2100 cm2

Area of other 4 surfaces = 2 (2800 + 1200 + 2100) cm^2 - 2 × 2100 cm^2

= 2 (2800 + 1200) cm^2

= 2 × 4000 cm^2

= 8000 cm^2

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