Rahim covers a distance of 48 km performed by
train, bike and car in that order, the distance cov-
ered by the three ways in that order are in the ratio
of 8:1:3 and charges per kilometer in that order
are in the ratio of 8: 1 :4: If the train charges being
24 Rs. per kilometer, the total cost of the journey is.?
Answers
Answer:
Rs.36
Step-by-step explanation:
total distance=48
the ratio of distance covered by transport are = 8:1:3
let the distance covered by train,bike,car=8x,1x,3x
therefore 8x+1x+3x=48
x=4
distance by train=32
distance by bike=4
distance by car=12
the ratio of cost=8:1:3
let the cost be 8z,1z,3z
therefore 8z +24
z=3
the cost of bike =3
cost of car=9
total cost =24+3+9=36
Answer:
924
Step-by-step explanation:
total distance - 48km
ratio of distance covered - 8:1:3 = Add all = 12
Distribution of all KM as 48/12 = 4
train= 4*8=32
bike = 1*4=4
bus = 3*4 = 12
now
charge = 8x : 1x : 4x
and value of 8x = 24 (Given)
x = 3
value of train = 32*24=768
value of bike = 1*3=3
value of car =4*3=12
cost incurred by bike = 3*4=12
cost incurred by car = 12*12=144
total cost = 144+12+768 = 924 .... Done