Question

Rahim covers a distance of 48 km performed by
train, bike and car in that order, the distance cov-
ered by the three ways in that order are in the ratio
of 8:1:3 and charges per kilometer in that order
are in the ratio of 8: 1 :4: If the train charges being
24 Rs. per kilometer, the total cost of the journey is.? ​

Answer 1

Answer:

Rs.36

Step-by-step explanation:

total distance=48

the ratio of distance covered by transport are = 8:1:3

let the distance covered by train,bike,car=8x,1x,3x

therefore 8x+1x+3x=48

x=4

distance by train=32

distance by bike=4

distance by car=12

the ratio of cost=8:1:3

let the cost be 8z,1z,3z

therefore 8z +24

z=3

the cost of bike =3

cost of car=9

total cost =24+3+9=36

Answer 2

Answer:

924

Step-by-step explanation:

total distance - 48km

ratio of distance covered - 8:1:3 = Add all = 12

Distribution of all KM as 48/12 = 4

train= 4*8=32

bike = 1*4=4

bus = 3*4 = 12

now

charge = 8x : 1x : 4x

and value of 8x = 24 (Given)

x = 3

value of train = 32*24=768

value of bike = 1*3=3

value of car   =4*3=12

cost incurred by bike = 3*4=12

cost incurred by car   = 12*12=144

total cost = 144+12+768 = 924 .... Done